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-9y^2-12y-4=0
a = -9; b = -12; c = -4;
Δ = b2-4ac
Δ = -122-4·(-9)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{12}{-18}=-2/3$
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